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	<title>Comments on: The 3rd of Twelvember</title>
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	<link>http://thebounder.co.uk/blog/151/the-3rd-of-twelvember/</link>
	<description>the home for all of jon bounds&#039;s nonsense</description>
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		<title>By: dp</title>
		<link>http://thebounder.co.uk/blog/151/the-3rd-of-twelvember/comment-page-1/#comment-107</link>
		<dc:creator>dp</dc:creator>
		<pubDate>Fri, 14 Mar 2008 16:14:27 +0000</pubDate>
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		<description>Make that Feb. 28 and 26 April.
http://www.timeanddate.com/date/dateadd.html</description>
		<content:encoded><![CDATA[<p>Make that Feb. 28 and 26 April.<br />
<a href="http://www.timeanddate.com/date/dateadd.html" rel="nofollow">http://www.timeanddate.com/date/dateadd.html</a></p>
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		<title>By: dp</title>
		<link>http://thebounder.co.uk/blog/151/the-3rd-of-twelvember/comment-page-1/#comment-106</link>
		<dc:creator>dp</dc:creator>
		<pubDate>Fri, 14 Mar 2008 16:06:12 +0000</pubDate>
		<guid isPermaLink="false">http://www.jonbounds.co.uk/ramblings/151/the-3rd-of-twelvember/#comment-106</guid>
		<description>Oh good, an opportunity to be silly by numbers!
Since a year is a cycle, it should be divisible by π, and its radius calculated.

So, if we correlate 365 days to 360 degrees, 365/2/π = 58.09 days, which puts the radius at about February 12. Double that to find the diameter of the year: April 17.

Care to represent that graphically? Jan 1 and April 17 should be opposite points on a circle. Erm.</description>
		<content:encoded><![CDATA[<p>Oh good, an opportunity to be silly by numbers!<br />
Since a year is a cycle, it should be divisible by π, and its radius calculated.</p>
<p>So, if we correlate 365 days to 360 degrees, 365/2/π = 58.09 days, which puts the radius at about February 12. Double that to find the diameter of the year: April 17.</p>
<p>Care to represent that graphically? Jan 1 and April 17 should be opposite points on a circle. Erm.</p>
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